Table 9 Calculate weight sum \(\:D_{L}\) of the positive distance from averaging.
 | \(\:\text T_{1}\) | \(\:\text T_{2}\) | \(\:\text T_{3}\) | \(\:\text T_{4}\) |
---|---|---|---|---|
\(\:{L}_{1}\) | \(\:\left\{\begin{array}{c}0.0075,\\\:0.0000\\\:0.0000,\\\:0.0000\end{array}\right\}\) | \(\:\left\{\begin{array}{c}0.0270\\\:,\:0.0000\\\:0.0000\\\:,0.0058\:\end{array}\right\}\) | \(\:\left\{\begin{array}{c}0.0000,\\\:0.0000\\\:0.0000,\\\:0.0000\end{array}\right\}\) | \(\:\left\{\begin{array}{c}0.0000,\\\:0.0000\\\:0.0206,\\\:0.0088\end{array}\right\}\) |
\(\:{L}_{2}\) | \(\:\left\{\begin{array}{c}0.0259\\\:,0.0000\\\:0.0000\\\:,0.0000\end{array}\right\}\) | \(\:\left\{\begin{array}{c}0.0000\\\:,\:0.0273\\\:0.0249\\\:,\:0.0000\end{array}\right\}\) | \(\:\left\{\begin{array}{c}0.0000,\\\:0.0151\\\:0.0000,\\\:0.0000\end{array}\right\}\) | \(\:\left\{\begin{array}{c}0.0199,\\\:0.0136\\\:0.0000,\\\:0.0000\end{array}\right\}\) |
\(\:{L}_{3}\) | \(\:\left\{\begin{array}{c}0.0000,\\\:0.0000\\\:0.0000,\\\:0.0000\end{array}\right\}\) | \(\:\left\{\begin{array}{c}0.0062\\\:,\:0.0159\\\:0.0000\\\:,\:0.0000\end{array}\right\}\) | \(\:\left\{\begin{array}{c}0.0542,\\\:0.0000\\\:0.0000,\\\:0.0000\end{array}\right\}\) | \(\:\left\{\begin{array}{c}0.0000,\\\:0.0000\\\:0.0000,\\\:0.0140\end{array}\right\}\) |
\(\:{L}_{4}\) | \(\:\left\{\begin{array}{c}0.0000\\\:,\:0.0503\\\:0.0113\\\:,\:0.0000\end{array}\right\}\) | \(\:\left\{\begin{array}{c}0.0000,\\\:0.0000\\\:0.0000,\\\:0.0000\end{array}\right\}\) | \(\:\left\{\begin{array}{c}0.0170,\\\:0.0461\\\:0.0000,\\\:0.0000\end{array}\right\}\) | \(\:\left\{\begin{array}{c}0.0461,\\\:0.0205\\\:0.0000,\\\:0.0000\end{array}\right\}\) |